how many mole of calcium carbonate are present in 10g of the substance ca=40 c=12 o=16
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1mole of CaCO3= Gram molecular mass of CaCO3=40+12+3×16=40+12+48=100gram.=1mole
100gram of CaCO3=1mole
1gram of CaCO3=1/100 mole
10gram of CaCO3=1/100×10=0.1 mole.
Therefore, 0.1 mole of CaCO3 is present in 10grams of the substance.
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mass of calcium carbonate = 10g
molecular mass of calcium carbonate =(1×40)+(1+12)+(3×16) =100g
number of moles in 100g calcium
carbonate = 1mole
therefore number of moles in 10g of calcium carbonate is 0.1.
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