How many mole of kclo3 needed to be heated to produce 11.35 litre oxygen at STP.
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The reaction is
2KClO3>2KCl+3O2
Considering it at NTP,
3moles O2=22.4×3=67.2 lO2
This vol is given by 2 moles of KClO3hence67.2
L will be given by 11.2×2/67.2=0.33 moles KClO3.
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