how many mole of Methane are required to produce 88 gram of carbon dioxide by combustion of Methane?
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Answer:
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CH4 + 2O2 -> CO2 + 2H2O
GRAM MOLECULAR MASS OF CO2 = 12 +2(16) = 44g
From the reaction it is clear that 1 mole of methane on complete combustion produces 44g (1 mole) of carbon dioxide.
therefore moles of CH4 required to produce 88g of CO2 are:
(88) * (1/44) = 2 moles
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