how many mole of NH3 gas present in the 44.8 litre?
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Answer:
Mass of 1 mol or (6.022×10
23
molecules) of NH
3
=14+3×1=17 g
Number o f molecules in 34 g NH
3
=
17
34
×6.022×10
23
=12.044×10
23
Number of atoms present in 1 molecule of NH
3
=4
Number of atoms in 34 g NH
3
=4×12.044×10
23
≈48×10
23
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