how many mole of water required to produce oxygen that was just sufficient to produce 800 gm of MGO by burning magnesium ribbon in presence of oxgen. where Atomic mass of mg is 24 u.
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given mass=800gm
molecular mass of MGO=24+16=40
Mole=given mass÷molecular mass
mole=800÷40=20
molecular mass of MGO=24+16=40
Mole=given mass÷molecular mass
mole=800÷40=20
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