Question

How Many molecule and atom of oxygen present in 5.6liter of oxygen at NTP?​

Answer 1

Answer:

Number of molecules = 1.5055 * 10²³

Number of atoms = 3.011 * 10²³

Explanation:

$\diamond$ We know that,

Number of moles = $\dfrac{Number \ of \ molecules}{Avogadro \ Number}$

Number of moles = $\dfrac{Volume (in \ litres)}{22.4}$

$\diamond$ Therefore,

$\dfrac{Number \ of \ molecules}{Avogadro \ Number} =\dfrac{Volume(in \ litres)}{22.4}$

$\diamond$ Given that,

Volume in litres = 5.6 litre

Avogadro Number = 6.022 * 10²³

$\diamond$ Substituting these values in we get,

$\dfrac{Number \ of \ molecules}{6.022 * 10^{23}}= \dfrac{5.6}{22.4}$

Number of molecules = $\dfrac{1}{4}*6.022*10^{23}$

Number of molecules = 1.5055 * 10²³ of O₂

$\diamond$ 1 molecule O₂ $\implies$ $2 \ atoms \ of \ O$

$\diamond$ 1.5055 * 10²³ molecules O₂ $\implies$ 1.5055 * 10²³ * 2 atoms of O

                                                $\implies$ 3.011 * 10²³ atoms