how many molecules and atoms of oxygen are present in 5.6 liter of oxygen gas at ntp
Answers
Answered by
2
Answer:
5.6l of O2 means we have 0.25 moles of O2. and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O.
Answered by
0
Answer:Molar volume of Oxygen =11.2L
Hence, 11.2L contains 6.022×10
23
atoms.
Hence for 5.6L, no. of atoms =6.022×10
23
×
11.2
5.6
No. of atoms =3.01×10
23
atoms
PLEASE LIKE
THANKU
Similar questions