Question

how many molecules and atoms of oxygen are present in 5.6 liter of oxygen gas at ntp

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Answer 1

Answer:

5.6l of O2 means we have 0.25 moles of O2. and as 1 molecule of O2 has 2 atoms, so, 1.50575*10^23 molecules will have 2*1.50575*10^23 atoms=3.0115*10^23 atoms of O.

Answer 2

Answer:Molar volume of Oxygen =11.2L

Hence, 11.2L contains 6.022×10

23

atoms.

Hence for 5.6L, no. of atoms =6.022×10

23

×

11.2

5.6

​

No. of atoms =3.01×10

23

atoms

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