How many molecules are in 98.3 grams of aluminum hydroxide
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Explanation:
no of molecules =moles ×Na
no of moles = 98.3÷78
moles =1.26moles of alumium hydroxide
no of molecules = 1.26×Na
no ofmolecules =7.58×1023
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molar mass of aluminium hydroxide
=1×27+3×16+3×1
=27+48+3
=78g
hence,78g of al(oh)3 =one mole
than 98.3g of mole=98.3/78
=1.26 moles
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