Question

how many molecules are present in 0.48g of so3​

Answer 1

Answer:

Explanation:

mass = 0.48 g

molar mass of SO₃ = 32 + 16 × 3

                               = 32 + 48

                               = 80 g

(∵ molar mass of sulphur = 32u , molar mass of oxygen = 16u)

moles = mass / molar mass

          = 0.48/80

          = 0.006 mol

no of molecules= moles × Na ( avogadro's no. = 6.02 × 10²³)

                          = 0.006  × 6.02 × 10²³

                          = 3.612 × 10²¹