How many molecules are present in 4.25 gram of nh3?
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No of molecules=n ×na(avagadro's no) ×1
No of molecules=4.25÷17 × 6.02×10^23= 1.505×10^23
No of molecules=4.25÷17 × 6.02×10^23= 1.505×10^23
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