Question

How many molecules are present in 45 grams of glucose?​

Answer 1

Answer ✅

: The molar mass of glucose can be calculated from the molar masses of individual atoms present in it. From the molecular formula, C6H12O6, one can find there are 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms in one molecule of glucose.

Answer 2

Answer: 1.505 X $10^2^3$ molecules are present in 45 grams of glucose

Explanation:

Now here,

Chemical Formula of Glucose = $C_6H_1_2O_6$

We know that,

To find out the molecules, first of all, we are required to find out the no.of mole, because

1 mole = 6.022 × $10^2^3$ molecules

Therefore,

No. of mole = $\frac{Mass of glucose}{molar mass of glucose}$

The molar mass of Carbon (C) = 12 gm/mol

The molar mass of Hydrogen (H) = 1 gm/mol

The molar mass of Oxygen (O) = 16 gm/mol

The molar mass of glucose = (6 X C) + (12 X H) + (6 X O)

                                             = (6 X 12) + (12 X 1) + (6 X 16)

                                             = (72 + 12 + 96)

                                             = 180 gm/mol

Now,

We have, the mass of the glucose = 45 grams

Therefore,

No. of mole = $\frac{Mass of glucose}{molar mass of glucose}$  =  $\frac{45}{180}$ = 0.25 moles

Now for molecules of glucose,

1 mol of glucose = 6.022 X $10^2^3$ molecules

0.25 mol of glucose = X molecules

Therefore,

X molecules = $\frac{6.022 X 10^2^3 X 0.25 }{1}$ = 1.505 X $10^2^3$ molecules.

Hence, 1.505 X $10^2^3$ molecules are present in 45 grams of glucose

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