Question

How many molecules are present in 69 g of ethanol ?​

Answer 1

9.019 × 10²³ molecules

Explanation:

Molecular weight of ethanol = 46.07 g,

NA = Avagadro's Number = 6.022 × 10²³

We know that,

NA number of molecules = Molecular weight of the molecule

6.022 × 10²³ number of molecules in 46.07 g of ethanol

∴ x number of molecules in 69 g ethanol

∴ x = 69 × 6.022 × 10²³/ 46.07

     = 9.019 × 10²³ molecules