Question

how many molecules are present in 8.0g of oxygen​

Answer 1

1 g contains → 6.022 × 1023 / 32 molecules of di oxygen. ⇒ 1 g contains → 0.188 × 1023 molecules of di oxygen. ∴ 8 g contains → 0.188 × 8 × 1023 molecules of di oxygen. =1.505 * 1023 molecules

Answer 2

Answer:

1 g contains → 6.022 × 1023 / 32 molecules of di oxygen. ⇒ 1 g contains → 0.188 × 1023 molecules of di oxygen. ∴ 8 g contains → 0.188 × 8 × 1023 molecules of di oxygen. =1.505 * 1023 molecules.