how many molecules are present in 8.0g of oxygen
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1 g contains → 6.022 × 1023 / 32 molecules of di oxygen. ⇒ 1 g contains → 0.188 × 1023 molecules of di oxygen. ∴ 8 g contains → 0.188 × 8 × 1023 molecules of di oxygen. =1.505 * 1023 molecules.
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1
Answer:
1 g contains → 6.022 × 1023 / 32 molecules of di oxygen. ⇒ 1 g contains → 0.188 × 1023 molecules of di oxygen. ∴ 8 g contains → 0.188 × 8 × 1023 molecules of di oxygen. =1.505 * 1023 molecules.
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