how many molecules are present there in 140g of mgo
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MgO=24+16=40g
Moles=mass/molar mass
=140/40=3.5moles
Molecules in 1 mole=6.023*10^23
=3.5*6.023*10^23
=21.0805*10^23molecules
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Moles=mass/molar mass
=140/40=3.5moles
Molecules in 1 mole=6.023*10^23
=3.5*6.023*10^23
=21.0805*10^23molecules
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Answer:
Molar mass of MgO = (24+16) gm
=40gm
since, 40 gm of MgO contains 6.022 × 10²³ molecules
therefore, 140gm will contain = (6.022 × 10²³ ÷40) ×140
=21.077 ×10²³ molecules
Explanation: First we will find that weight of 6.022 × 10²³ molecules in MgO i.e it's molar weight or molar mass then we will find out the no. of molecules in 1 gm of MgO and after doing so to find out the no. of molecules in 140gm of MgO we will apply unitary method i.e we will multiply the weight of 1 gm of MgO by 140 to find out the no. of molecules in 140 gm of MgO
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