Question

How many molecules are there in 345 grams of carbon dioxide?

Answer 1

Answer:

47.21*10^23

Explanation:

345%44 *NA

formula is :

no. of molecule= no. of moles *NA

since, no. of moles=mass%molecular mass

=345%44

=7.84

NA(avagadro no. )= 6.022*10^23

therefore, =7.84*6.022*10^23

= 47.21*10^23

Answer 2

$4.7\times 10^{24}$ molecules of carbon dioxide $(CO_2)$ are there in 345 grams of carbon dioxide

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{345g}{44g/mol}=7.8moles$

1 mole of carbon dioxide $(CO_2)$ contains= $6.023\times 10^{23}$ molecules of carbon dioxide

Thus 7.8 moles carbon dioxide $(CO_2)$ contain= $\frac{6.023\times 10^{23}}{1}\times 7.8=4.7\times 10^{24}$ molecules of carbon dioxide

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