Chemistry, asked by Muhammadayazkhan, 2 months ago

how many molecules are there in 75 mg 0f NO2?​

Answers

Answered by saka82411
3

Answer:

9.82 × 10^20 molecules

Explanation:

No. of moles (n) = Mass/ Molar Mass

:- n = 75×10^-3/ 46

:- n = 0.001630 moles.

1mole = 6.023 ×10²³ molecules

:- 0.001630 mole = X

x = 9.82 × 10^20 molecules.

Hope it helps.

Answered by Anonymous
2

Explanation:

 \large{ \pink{ \underline{ \bold{ \blue{Given :-}}}}}

 \bold{Given \:  mass  \: of \:  NO_2 = 75 g}

 \bold{Atomic \:  mass \:  of \:  O \:  = 16 g}

 \bold{Atomic \:  mass  \: of \:  N = 14 \:  g}

 \bold{Molecular  \: mass \: of \:  NO_2 = 14  + 2 \times 16}

 \bold{ = 14 + 32 = 46 \: g}

 \bold{Number  \: of  \: molecules  = 75 \times\frac{1}{46} \times 6.022 × 10^{23}}</p><p>

 = 1.63 × 6.022 × 10^{23}

 = 9.81586 \times  {10}^{23}

 \bold{Number  \: of  \: molecules \:  9.81586  \times  10^{23} \:  molecules.}

I hope it is helpful for you

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