How many molecules of 02 are present in 1 L air containing 80 % volume of 0 2 at STP ?
Answers
Answered by
0
hope this helps you....
Attachments:
Answered by
2
Answer:
Answer: 2.15x 10^22 molecules.
Explanation:
▪️ Correct question should be: how many molecules of oxygen are present in 1 litre of air containing 80% of O2.
First, we will have to find amount of energy in one oxygen.
Therefore,
➡️ Amount of oxygen present in 1 litre air is = 80% *1000 ml
➡️ (80/100)*1000
=800ml
▪️ We know that, 1 mole of STp occupies 22.4 litre
It is equal to = 22400ml of O2 gas contains 6.022x 10^23 molecules
So,
➡️ 1ml of O2 gas Contains =6.022x10^23/22400
According to question, we have to find 800ml molecules.
Therefore,
800ml contains =(6.022x 10^23/22400) *800
=> 2.15 x 10^22
▪️ Hence, molecules present in 1 litre air containing 80% volume of at STP is 2.15x 10^22 molecules.
Similar questions