Question

How many molecules of ammonia are present in 34 g of ammonia?

Answer 1

1 mole = 6.022*10²³ 2 moles = 6.022*10²³ * 2 = 12.044 * 10²³ therefore 34 g of NH₃ contains 12.044*10²³ molecules .

Answer 2

Answer:

12.044 × 10^23

Explanation:

no of molecules = given mass / molar mass × 6.022 × 10^23

molar mass of ammonia = atomic mass of nitrogen * 1 + atomic mass of hydrogen*3

14 × 1 + 1 × 3

14+3=17 g

34/17 × 6.022 × 10 ^23 =12.044 × 10^23

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