How many molecules of an ideal gas are there in 1 ml of the gas if the temperature is 27c and the pressure is 3 atm
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Answer:use PV=nRT
Now we have to find n therefore
n=PV/RT
Substitute the values
n=3×1/8.314×300
= 0.12079×6.023 ×10²³
0.000724×10²³
Therefore 7.24×10¹⁹
Explanation:temperature =27+273=300
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