How many molecules of benzene are
there in 1L
of C6H6 [d=0.88g/cm3]???
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Explanation:
Given -
- 1 L C6H6, density(d) = 0.88 g/cm³
To Find -
- How many molecules of benzene are there in 1 L of C6H6
Solution -
d = m/v
0.88 = m/1 × 1000
m = 0.88 × 1000
m = 880
Now,
As we know that -
- mole = mass/GMM
n_{C6H6} = 880/78
n_{C6H6} = 11.282
Then,
Number of molecules = n × 6.022 × 10²³
= 11.282 × 6.022 × 10²³
= 67.94 × 10²³
Hence,
The number of molecules present in 1 L of C6H6 is 67.94 × 10²³.
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