Question

How many molecules of chlorine should be deposited?

Answer 1

Answer:

1) We have reaction, 

2Cl(-) -----> Cl2 + 2e-

no. of electrons losed per unit of species, n = 2 

Current, I =300mA= 0.3 A 

Time till current was passed, t = 60 s 

Molar Mass of Cl2 = 35.5*2 = 71 g 

Then, no. of molecules of Cl2 

= (Mass deposited/ Molar Massof Cl2) * ( 6.022 * 10^(23 ) 

= (W/M) * 6.022 * 10^(23 )

= (M/nFM) * (Q) * (6.022 * 10^(23 )

now u can calculate this.

Explanation:

This is solved from molten NaCl.

bt ur question is half.Please improve this.