Question

How many molecules of chlorine should be deposited from molten sodium chloride in one minute by a current of 300 milliamperes

Answer 1

Answer:

Final Answer : 5.62 * 10^(19) molecules

Steps:

1) We have reaction,

2Cl(-) -----> Cl2 + 2e-

no. of electrons losed per unit of species, n = 2

Current, I =300mA= 0.3 A

Time till current was passed, t = 60 s

Molar Mass of Cl2 = 35.5*2 = 71 g

2) By Faraday's Law of electrolysis,

Mass of Cl2 (Chlorine) deposited,

W : (M/nF)* (Q)

We have, M = 71 g

n = 2

1 F = 96,500C

Q = Charge passed through it = I *t

= 0.3 * 60 = 18 C

3) Then, no. of molecules of Cl2

= (Mass deposited/ Molar Massof Cl2) * ( 6.022 * 10^(23 )

= (W/M) * 6.022 * 10^(23 )

= (M/nFM) * (Q) * (6.022 * 10^(23 )

Hence, No. of molecules of Cl2 is 5.62 * 10^(19)

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Explanation: