How many molecules of chlorine should be deposited from molten sodium chloride in one minute by a current of 300 milliamperes
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Answer:
Final Answer : 5.62 * 10^(19) molecules
Steps:
1) We have reaction,
2Cl(-) -----> Cl2 + 2e-
no. of electrons losed per unit of species, n = 2
Current, I =300mA= 0.3 A
Time till current was passed, t = 60 s
Molar Mass of Cl2 = 35.5*2 = 71 g
2) By Faraday's Law of electrolysis,
Mass of Cl2 (Chlorine) deposited,
W : (M/nF)* (Q)
We have, M = 71 g
n = 2
1 F = 96,500C
Q = Charge passed through it = I *t
= 0.3 * 60 = 18 C
3) Then, no. of molecules of Cl2
= (Mass deposited/ Molar Massof Cl2) * ( 6.022 * 10^(23 )
= (W/M) * 6.022 * 10^(23 )
= (M/nFM) * (Q) * (6.022 * 10^(23 )
Hence, No. of molecules of Cl2 is 5.62 * 10^(19)
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