Question

How many molecules of CO2 will be needed to obtain 1.8 g of glucose according to given reaction.Reaction : 6CO2 + 6H2O ¾® C6H12O6 + 6O2[M. wt C6H12O6 = 180 g mol–1](C = 12, H = 1, O = 16)


(A) 0.6 × 6.022 × 1023

(B) 6 × 6.022 × 1023

(C) 0.06 × 6.022 × 1023

(D) 60 × 6.022 × 1023​

Answer 1

Haha chemistry go because c is answer

Answer 2

Answer:

6H2O+6CO2→C6H12O6+ 6O2.