How many molecules of H²SO⁴ are there in 49g sample ?
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Hello friend
____________________________
Let's write the given:
Mass of Sulphuric (H2SO4) = 49g
We have the number of molecules in 49g of H2SO
explanation=)
Molecular mass of H2SO4 = (Atomic mass of H) x 2 + (Atomic mass of S) x 1 + (Atomic mass of O) x 4
Molecular mass of H2SO4 = ( 1 x 2) + (32 x 1) + (16 x 4)
= 2 + 32 + 64
= 98.
Now,
According to the formula,
Number of moles in the given H2SO4(n)
= Mass of H2SO4 in grams/Molecular mass of H2SO4
= 49/98
= 1/2
= 0.5
: n = 0.5 mol
: 1 mol of H2SO4 contains 6.022 x 10^23 molecules.
: 0.5 mol of H2SO4 contains 0.5 x 6.022 x 10^23 molecules.
= 3.011 x 10^23 molecules
that is 49 g of H2SO4 contains 3.011 x 10^23 molecules of H2SO4.
THANKS
:)
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