Question

How many molecules of HCl are in 4.91 L of HCl acid at 25°C if the density equals 1.096 g/mL?

Answer 1

Answer:

How many molecules of HCl are in 4.91 L of HCl acid at 25°C if the density equals 1.096 g/mL? a. 5381.4 b. 8.89 x 1025 4.91 10mL c. 3.24 x 1027 ml 4,912 103 m 4910 4910 mL k=273.15+C (F-32x5/6 8. What is the temperature of 273 K expressed in "F? a. 31.73 b. 0 c. 50.5 273=273.15+C d. 20.73 6. What is the density of a 10.5 g sample of an unknown metal if it displaces 25.5 mL of water when placed inside a graduated cylinder that contains 50.0 mL of water? a. 0.429 g/mL b. 0.210 g/mL 10.sg (c, 0.412 g/mL 25.5 mL d. 4.20 g/mL

its the answer.....

Answer 2

4.91L=4910mL. The mass is 4910×1.096g=5381.36g.

Step-by-step explanation:

• Using Avogadro’s number 6.022×10²³ which relates the molecular mass to mass in grams.
• and using H=1 and CL=35.5 as atomic weights, the molecular mass is 36.5 approx, so 36.5g contain 6.022×10²³ molecules.
• 5381.36containg5381.36/36.5×6.022×10²³
• =887.85×10²³
• =8.8785×10²⁵ molecules.
• Round this because of approximations to 8.88×10²⁵ molecules.