How many molecules of HCL will be required to have 10 g of it . please solve this numerical
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1 MOLE OF HCI THAT IS 36.5g CONTAINS6.022*10^23 MOLECULES
HENCE TO MAKE 10g OF HCI,WE HAVE TO DIVIDE 36.5/Na AND MULTIPLY IT BY 10
HENCE UR ANSWER IS 6.061*10^-22 molecules
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