how many molecules of HCL will be required to have 10 grams of it
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Answered by
10
Answer:
1.649 * 10^23 molecules
Explanation:
m/M= N/N₀ (mole concept)
10/36.5= N/6.022 * 10^23
N = 6.022 * 10^24/36.5
N = 0.1649 * 10^24
= 1.649 * 10^23 molecules
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Answered by
1
Answer:
1.696 × 10^23
Explanation:
you can refer above image
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