How many molecules of HCL will be required to make 10g of it?
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Answer:
1 mole of HCl that is 36.5 g contains 6.022*10^23 molecules
Hence to make 10 g of HCl , we have to divide 36.5/ Na and multiply it by 10
Hence ur answer is 6.061*10^ -22 molecules
Hope it helps you
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