Question

HOW MANY MOLECULES OF HYDROGEN WILL BE PRESENT IN 68 GM H2O2? (H2O2 = 34 GM/MOLE)

Answer 1

Explanation:

Molecular Mass of H2O2 = 34

Mass given = 68g

Mole = Mass / molecular mass

Mole = 68/34

Mole = 2

Mole = No. of. molecules / Avogadro number

[Substituting Mole = 2, Avogadro number = 6.022×10²³]

2 = No. of. molecule / 6.022×10²³

No. of molecule = 6.022×10²³×2

No of molecule = 12.044× 10²³

Answer 2

Answer:

The number of molecules of hydrogen peroxide present in 68g of  H₂O₂ is equal 12.046×10²³.

Explanation:

We know the molecular weight of H₂O₂ $=34gmol^{-1}$

Given mass of H₂O₂ $=68g$

Number of moles = (mass of H₂O₂)/(molecular mass)

                            $=\frac{68}{34}=2mol$

We can find the number of molecules by multiplying the number of moles by Avogadro number .

Number of moles = (No. of molecules)/(Avogadro number)

⇒   $2=\frac{N}{6.023*10^{23}}$

Number of molecules (N) $=2*6.023*10^{23}$

                                         $=12.046*10^{23}$

Therefore, the number of molecules of H₂O₂ is equal to 12.046×10²³ in 68g of hydrogen peroxide of gas.