how many molecules of N2 gas are present in 22400 litre of N2 gas at STP
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in 22.4 litres ----> 6.023x10²³ molecules
so in 22400 litres ------> x molecules
x= 6.023 x 10²³ x 22400/22.4
x= 6.023 x 10^26 molecules
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Answer:
6.023*10^26
Explanation:
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