Question

How many molecules of nitrogen gas are found in 2.4 L of nitrogen gas at STP?

Answer 1

Answer:

6.44 * 10^22 molecules

Explanation:

PV = nRT

now, n = N/Na(Avogadro number)

Thus, at STP,

PV = (N/Na)*R*T

or, N = (P*V*Na)/(R*T) = (1 * 2.4 * 6.023*10^23) / (0.0821 * 273) = 6.44 * 10^22