Question

how many molecules of oxygen are present in 1 litre air containing 80% volume of oxygen at STP​

Answer 1

Answer:

Explanation:

1 litre of air contains 80% O2O2 by volume. So O2O2is 0.8 L.

At STP, 1 mole of O2O2 occupies 22.4 L. Hence , we can find how many moles occupy 0.8 L by n=0.822.4=0.0357n=0.822.4=0.0357 .

1 mole contains avagadro number(6.023×10236.023×1023) of particles.

So, 0.0357 moles contain

0.0357 ×6.023 ×1023 =2.15 × 10220.0357 × 6.023 × 1023 = 2.15×1022  molecules.

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