Question

How many molecules of So2 gas weigh same as 240* 10²³ molecules of nitrogen gas?​

Answer 1

Answer:

Given,

molecules of N2 = 240 × 10^23

no. of moles of N2 = No. of molecules/ Avogadro No.

nN2 = 240 × 10^23/6 × 10^23 = 40 moles

We know, n = mass/molar mass

let mass of N2 be x g,

molar mass of N2 = 14 × 2 = 28 g

so, 40 = x/28 g

x = 40 × 28 g = 1120 g

Since, we want the mass of SO2 to be equal to that of N2,

therefore, mass of SO2 = 1120 g

Molar mass of SO2 = 32 + 16 × 2 = 32 + 32 = 64 g

No. of moles of SO2 = 1120g / 64g

nSO2 = 17.5 moles

Now, no. of molecules = No. of moles × Avogadro no.

so, no. of molecules of SO2 = 17.5 × (6 × 10^23) = 105 × 10^23 molecules