Question

How many molecules of sucrose are contained in 14.3 mL of 0.140 M sucrose solution?

Answer 1

Explanation:

Explanation:

Molarity ofsucrose solution= 0.140M

Volume of sample= 14.3 mL or 14.3*10^-3 litres

No. Of moles of sucrose = Molarity*Volume

Therefore no. Of moles =0.140*14.3*10^-3= 2*10^-3

1 mole sucrose contains 6.022*10^23 molecules

So 2*10^-3 moles contains 2*10^-3*6.022*10^23= 1.2044*10^21 molecules