Chemistry, asked by Mohammedyounas7750, 11 months ago

How many molecules of sulphur are present in 12.8g sulphur

Answers

Answered by yashu2256
0

Answer:

2.4×10^23

Explanation:

For 32 grams of sulphur 6.023×10^23

For 12.8 grams 12.8×6.023×10^23/32=2.4×10^23

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