Chemistry, asked by muskansingh050120200, 10 months ago

How many molecules of water of crystallization are present in 1.648g of copper sulphate (CuSO4.5H2O). [At mass of Cu=63.5, S=32,O=16, H=1]

Answers

Answered by trmanormak
0

Answer:The molecular weight of water H

2

O=2(1)+16=18g/mol.

The molecular weight of copper sulphate pentahydrate CuSO

4

.5H

2

O=64+32+4(16)+5(18)=250g/mol.

The percentage of water of crystallization in CuSO

4

.5H

2

O=

250

5×18

×100=36%.

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