Question

how many molecules of water of hydration are present in 252mg of oxalic acid ​

Answer 1

Number of molecules available in oxalic acid is equal to 630 divided by 126 which come to 5.

 Number of molecules of water present is equal to 5 x 6.02 x 10 ^ 23

Therefore, number of molecules of water of hydration present in 630 mg oxalic acid is 30.1 x 10^ 23.