how many molecules of water of hydration are present in 630mg of oxalic acid
Answers
Answered by
1
PLEASE MARK IT AS A BRAINLIEST AND FOLLOW ME
Answer:
Number of molecules available in oxalic acid is equal to 630 divided by 126 which come to 5. Therefore, number of molecules of water of hydration present in 630 mg oxalic acid is 30.1 x 10^ 23.
Answered by
2
Explanation:
i think it will be helpful to you
Attachments:
Similar questions