Question

how many molecules of water of hydration are present in 39.2 mg of of Mohr's salt {FeSO4.(NH4)2.SO4.6H2O}...????​

Answer 1

molar mass = 392 g/mol

(39.2 mg) x (1 g/1000 mg) x (1mol / 392 g) x (6.022 x 1023 formula units / mole) x (6 molecules water / Formula unit) = 3.6132 x 1020 molecules.

Answer 2

Answer:

Hey mate..!!

Explanation:

molar mass = 392 g/mol

molar mass = 392 g/mol(39.2 mg) x (1 g/1000 mg) x (1mol / 392 g) x (6.022 x 1023 formula units / mole) x (6 molecules water / Formula unit) = 3.6132 x 1020 molecules.

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