Chemistry, asked by DynamicDhruv5617, 11 months ago

How many molecules of waterer there in 8.050*10^3 grams of water

Answers

Answered by TechUpWithArvind
16

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The mass of one mole of water is 18 grams. To determine the number of moles of water, divide this mass by 18.

n = 8.050 * 10^3 ÷ 18

This is 477 and 2/9th moles.

N = 6.02 * 10^23 * 8.050 * 10^3 ÷ 18 = 4.8461 * 10^27 ÷ 18

This is approximately 2.69 * 10^26 molecules. I hope this is helpful for you.

Answered by fiberbishop
0

Answer:

2.69 * 10^26 molecules

Explanation:

8.050 * 10^3 g H2O * (1 mol/18g) * (6.02 * 10^23 molecules/1 mol) = 2.69 * 10^26 molecules

2.69 * 10^26 molecules  final answer

(round to 3 sig figs b/c 6.02 is three digits)

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