Question

how many molecules present in 0.0933 mol of NaOH​

Answer 1

Answer:

$No. \: of \: atoms \: in \: 1 \: mole \: of \: NaOH \: = NA \: = \\ 6.02× {10}^{23} \\ ∴ No. \: of \: atoms \: in \: 0.01 \: moles \: of \: NaOH \: =  \\ 6.02× {10}^{23} ×0.01 \\ =6.02× {10}^{21}$

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