how many molecules will be present in 0.2 moles of cacl2?
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Explanation:
0.4 moles
HCl
⇌H
+
+
0.4 moles
Cl
−
0.2 moles
CaCl
2
⇌Ca
2+
+
2×0.2=0.4moles
2Cl
−
Total Cl
−
moles=0.4+0.4=0.8 moles
Molarity=
Vol.inL
moles
∴ Molarity of Cl
−
=
0.5
0.8
=1.6M.
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