Question

how many moles and numbers of molecules in 29 gm magnesium hydroxide​

Answer 1

Answer:

3.0115×1023molecules.

1 mole of MgO contains Avogadro's number of molecules which is 6.023×1023 molecules.

1 mole of MgO contains Avogadro's number of molecules which is 6.023×1023 molecules.0.5 mole of MgO will contain 0.5×6.023×1023=3.0115×1023 molecules.

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Answer 2

Given Mass :- 29 GM

molar mass of Mg(OH)2

$molar \: mass \: of \: mg(oh) \frac{}{2}$

n=m/M

$n = \frac{m}{m}$

n= 29/58

n= 1/2 mole

$n = \frac{1}{2} mole$