How many moles are 9.033*10^24atoms of helium
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Answer:
14.99 moles
Explanation:
We must know that, Avogadro's number is numerically equal to 6.023 * 10^23 !
It is a fact that,
1 mole of any element or molecule = The Avogadro's number
=> 1 mole of Helium = 6.023 * 10^23 particles(or atoms)
The above sentence can also be written as,
=> There are 6.023 * 10^23 particles in 1 mole of Helium.
=> There is 1 particle in 1/(6.023*10^23) moles of Helium.
=> There are 9.033 * 10^24 particles in { 1/(6.023*10^23) * 9.033 * 10^24 } moles of Helium.
=> There are 9.033 * 10^24 particles in 1.499 * 10 moles of Helium.
=> There are 9.033 * 10^24 particles in 14.99 moles of Helium.
Hence,
14.99 moles of Helium = 9.033 * 10^24 particles of Helium
#bal
#answerwithquality
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