Chemistry, asked by mdiaz905ouyi8x, 1 year ago

How many moles are found in a 3.8g sample of NaBH4

Answers

Answered by myrakincsem
0
Thank you for asking this question. i will let you in finding the true answer.
 The number of mole is defined by the ratio of mass or weight of the substance to the molar mass of substance or compound

As Number of moles = Mass of substance/molar mass of substance

As the mass here is 3.8 grams while the number of moles of NaBH4(sodium borohydride) is 37.83g/mol. we are taking the round about value of molar mass as 38 here.
So putting values in formula :
Number of moles of NaBH4= Mass or weight of NaBH4/molar mass of NaBH4
Number of moles of NaBH4= 3.8/38 = 0.1 moles 
So 0.1 moles will be present in 3.8 grams of NaBH4.
Answered by prmkulk1978
1
Given compound SODIUM Boron Hydride.
NaBH4.
Molecular mass of NaBH4
= sum of atomic masses of Na + atomic mass of B+ Atomic mass of H
= 23+11+4×1
=23+11+4
=38 unified mass
Therefore molar mass of NaBH4= 38g
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Formula to be used:
Number of moles =Given weight/ molar mass
=3.8/38
=38/38*10
=0.1 moles
********************************************
THEREFORE NUMBER OF MOLES IN 3.8g of NaBH4 is 0.1
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