Question

how many moles are in 68 grams of copper (ii) hydroxide,Cu(OH)2?

Answer 1

Answer:

here are

0.70

moles of Cu(OH)2 .

Explanation:

We can use the following formula to determine the number of moles:

m=nM

where:

m = mass (grams)

n = number of moles

M = molar mass

To find the number of moles, we first have to find the molar mass of

Cu(OH)2 . We can do this by adding the molar masses of copper, oxygen, and hydrogen together, accounting for the number of atoms for each element.

M

copper=63.55gmol

Mhydrogen

=1.01gmol⋅2=2.02gmol

M oxygen=16.00g mol⋅

2 = 32.00gm mol

M

copper (II) hydroxide

=63.55gmol+2.02gmol+32.00gmol=97.57gmol

Now we can substitute our known values into the formula to solve for number of moles:

m=nM

n=mM

n=68g÷97.57gmol

n=68g⋅mol97.57g

n=68g⋅mol97.57

n=68mol97.57

n=0.6969355335mol

n= 0.70mole

Note:

The final answer should always have the correct number of significant figures.

∴ , there are 0.70 moles of Cu(OH)2 .