Question

How many moles are in 98.3 grams of aluminum hydroxide al(oh)3?

Answer 1

molar mass of aluminium hydroxide


=1×27+3×16+3×1


=27+48+3

=78g

hence,78g of al(oh)3 =one mole

than 98.3g of mole=98.3/78

=1.26 moles



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Answer 2

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molar mass of aluminium hydroxide

=1×27+3×16+3×1

=27+48+3

=78g

hence,78g of al(oh)3 =one mole

than 98.3g of mole=98.3/78

=1.26 moles