How many moles are in a 28.35 g sample of CaCO3? (Round your answer to 2 digits.) *
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Answer:
0.28 moles
Explanation:
In 10g of CaCO3= 1/100×10 = 0.1 mole
So, in 28.35g of CaCO3= 1/100×28.35 = 0.2835
Rounding off in two digits = 0.28 mole
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