How many moles are present in 34 gram of NH3
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Atomic mass of NH3 = 14 + 3 x 1 = 17
17 g of NH3 atoms = 1 mole
34 gm of NH3 atoms
17 g of NH3 atoms = 1 mole
34 gm of NH3 atoms
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NH3=14+1×3
=17 u
1 mole=17g
Therefore, number of moles 34g
=given mass / molar mass
=34/17
=2 moles
Therefore,
1 mole=6.022×10²³
2 mole=6.022×10²³×2
=12.044×10²³
Therefore, 34g of NH3 contains 12.044×10²³
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NH3=14+1×3
=17 u
1 mole=17g
Therefore, number of moles 34g
=given mass / molar mass
=34/17
=2 moles
Therefore,
1 mole=6.022×10²³
2 mole=6.022×10²³×2
=12.044×10²³
Therefore, 34g of NH3 contains 12.044×10²³
Hope it help u....
plz mark me brainlist......
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